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Comment by throwawayReply

Given it's all multiplied it doesn't matter if the luck is from 0-1000 or 0-1, it has the same effect on the outcome.

a * (b * 1000) = (a * 1000) * b

Sorry, I hate bad maths, I realise it is just trying to imply that luck is more important, but in that case it should be * luck^n.

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